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At what temperature , will the rms speed...

At what temperature , will the rms speed of oxygen molecules be sufficient for escaping from the earth ? Take `m = 2.76 xx 10^(-26) kg, k = 1.38 xx 10^(-23) J//K and v_(e) = 11.2 km//s`.

A

`5.016xx10^(4) K`

B

`8.326xx10^(4)K`

C

`2.2508xx10^(4) K`

D

`1.254xx106(4) K`

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The correct Answer is:
B
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At what temperature , will the rms speed of oxygen molecules be sufficient for escaping from the earth ? Taken m = 2.76 xx 10^(-26) kg, k = 1.38 xx 10^(-23) J//K and v_(e) = 11.2 km//s .

At what temperature will the average velocity of oxygen molecules be sufficient to escape from the earth. Given mass of oxygen molecule = 5.34 xx 10^(-26) kg . Boltzmann constant, k = 1.38 xx 10^(-23) J "molecule"^(-1) K^(-1) . Escape velocity of earth = 11.0 km s^(-1) .

Does a rocket really need the escape speed of 11.2 km//s initially to escape from the Earth?

The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to: [Boltzmann constant k _ B = 1.38 xx 10 ^( -23) J//K Avogadro Number N _ A = 6.02 xx 10 ^( 26) // Kg Radius of Earth : 6.4 xx 10 ^( 6 ) m Gravitational acceleration on Earth = 10 ms ^( -2) ]

Energy of a particle at absolute temperature T is of the order kT. Calculate the wavelength of thermal neutrons at 27^(@)C . Take mass of neutron = 1.67 xx 10^(-27)kg, h =6.6 xx 10^(-34)Js and k = 1.38 J " mol"^(-1)K^(-1) .

At what temperature, hydrogen molecules will escape from the earth's surface ? (Take, radius of earth R_(e)=6.4xx10^(6)m , mass of hydrogen molecule m=0.34 xx 10^(-26) kg, Boltzmann constant k=1.38xx10^(-23)JK^(-1) and acceleration due to gravity = 9.8 xx ms^(-2) ) also take rms speed of gas as v_(rms) = sqrt((3kT)/(m)) .

What is the rms speed of oxygen molecules at 225^(@)C ? Density of oxygen at NTP is 1.42 kg m^(-3) and one atmosphere is 1.013xx10^(5)Nm^(-2) .

Imagine a planet whose diameter and mass are both one half of those of earth. The day's temperature of this planet surface reaches upto 800 K . ? Make calculation and tell whether oxygen molecules are possible in the atmosohere of the planet. [Escape velocity from earth's surface = 11.2 km//s, k = 1.38 xx 10^(-23)J//K , mass of oxygen molecule = 5.3 xx 10^(-26) kg ].

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