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A particle velocity changes from (2 hati...

A particle velocity changes from `(2 hati - 3hatj) ms^(-1)` to `(3hati - 2hatj) ms^(-1)` in 2s. If its mass is 1kg, the acceleraton `(ms^(-2))` is

A

`-(hati +hatj)`

B

`(hati + hatj)//2`

C

zero

D

`(hati -hatj)//2`

Text Solution

Verified by Experts

The correct Answer is:
B
`a = (v_(t)-v_(i))/(t) = ((3hati -2hatj)-(+2hatj-3hatj))/(2) = (hati +hatj)/(2)`
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