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A projectile is thrown at an angle theta...

A projectile is thrown at an angle `theta` with the horizontal and its range is `R_(1)`. It is then thrown at an angle `theta` with vertical anf the range is `R_(2)`, then

A

`R_(1) = 4R_(2)`

B

`R_(1) = 2R_(2)`

C

`R_(1) = R_(2)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C

We know that, `R_(theta) = R_(90^(@)-theta)`
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