The range of a projectile launched at an angle of `15^(@)` with horizontal is 1.5km. The range of projectile when launched at an angle of `45^(@)` to the horizontal is

Options

A. 1.5 km
B. 3 km
C. 6km
D. 0.75km

Answer

B

Explanation

`R_(15^(@)) = (u^(2)sin (2xx 15^(@)))/(g) = (u^(2))/(2g) = 1.5km`
`rArr R_(45^(@)) = (u^(2)sin (2xx 45^(@)))/(g) = (u^(2))/(g) = 1.5 xx 2 = 3km`