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Velocity and acceleration of a particle ...

Velocity and acceleration of a particle at some instant of time are `v = (3hati +4hatj) ms^(-1)` and `a =- (6hati +8hatj)ms^(-2)` respectively. At the same instant particle is at origin. Maximum x-coordinate of particle will be

A

1.5 m

B

0.75m

C

2.25m

D

4m

Text Solution

Verified by Experts

The correct Answer is:
B
`u_(x) = 3ms^(-1), a_(x) =- 6 ms^(-1)`
`:. X_(max) = (u_(x)^(2))/(2|a_(x)|) = (9)/(12) = 0.75m`
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