A projectile is fired from level ground at an angle `theta` above the horizontal. The elevation angle `phi` of the highest point as seen from the launch point is related to `theta` by the relation.

Options

A. `tan phi = (1)/(4) tan theta`
B. `tan phi = tan theta`
C. `tan phi = (1)/(2) tan theta`
D. `tan phi = 2 tan theta`

Answer

C

Explanation

`tan phi = (H)/(R//2) = (2H)/(R) = ((u^(2)sin^(2)theta//g))/(u^(2)sin 2theta//g)`
`tan phi = (sin^(2)theta)/(2sin theta cos theta) = (tan theta)/(2)`