Home
Class 11
PHYSICS
The ratio of the speed of a projectile a...

The ratio of the speed of a projectile at the point of projection to the speed at the top of its trajectory is x. The angle of projection with the horizontal is

A

`sin^(1) x`

B

`cos^(-1)x`

C

`sin^(-1) (1//x)`

D

`cos^(-1) (1//x)`

Text Solution

Verified by Experts

The correct Answer is:
D
Speed of projectile at the point of projection = u
Speed of projectile at the top of its trajectory `= u cos theta`.
`(u)/(u cos theta) = x` or `cos theta = (1)/(x) rArr theta = cos^(-1)((1)/(x))`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOTION

    DC PANDEY|Exercise B. Medical entrance|1 Videos

  • MOTION

    DC PANDEY|Exercise Medical entrance|12 Videos

  • MOTION

    DC PANDEY|Exercise A. Taking it together|1 Videos

  • MEASUREMENT AND ERRORS

    DC PANDEY|Exercise Subjective|19 Videos

  • MOTION IN A PLANE

    DC PANDEY|Exercise (C )Medical entrances gallery|32 Videos

Similar Questions

Explore conceptually related problems

The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is .

The horizontal range of a projectile is times of its maximum height. Its angle of projection will be :-

Knowledge Check

  • The trajectory of a projectile in a vertical plane is y=ax-bx^(2) , where a and b are constants and x and y are respectively horizontal and vertical distances of the projectile from the point of projection. The maximum height attained by the particle and the angle of projection form the horizontal are:

    A
    `(b^(2))/(2a), tan^(-1)(b)`
    B
    `(a^(2))/b, tan^(-1)(2b)`
    C
    `(a^(2))/(4b), tan^(-1)(a)`
    D
    `(2a^(2))/b, tan^(-1)(a)`

  • The total speed of a projectile at its greater height is sqrt(6/7) of its speed when it is at half of its greatest height. The angle of projection will be :-

    A
    `60^(@)`
    B
    `45^(@)`
    C
    `30^(@)`
    D
    `50^(@)`

  • The launching speed of a certain projectile is five times the speed it has at its maximum height.Its angles of projection is

    A
    `theta=cos^(-1)(0.2)`
    B
    `theta=sin^(-1)(0.2)`
    C
    `theta=tan^(-1)(0.2)`
    D
    `theta=0^(@)`

    • Similar Questions

    Explore conceptually related problems

    Average velocity of a particle in projectile motion between its starting point and the highest point of its trajectory is (projectin speed = u, angle projection from horizontal = theta )

    The speed of a projectile when it is at its greatest height is sqrt(2//5) times its speed at half the maximum height. The angle of projection is

    The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

    Two projectiles are projected simultaneously from the top and bottom of a vertical tower of height h at angles 45^(@) and 60^(@) above horizontal respectively.Body strike at the same point on ground at distance 20m from the foot of the tower after same time. The ratio of the speed of the projectile projected from the top and the speed of the projectile projected from the bottom of tower is

    Choose the correct option (i) The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is 60^(@) . (ii) A missile is fired for maximum range with an initial velocity of 20 m//s , the range of the missile is 40 m . (iii) A ball is projected with a kinetic energy E at an angle of 45^(@) to the horizontal. At the highest point during its flight, its kinetic energy will be E//2 . (iv) An object is projected at an angle of 45^(@) with horizontal. The horizontal range and the maximum height will be in the ratio 4:1

    Home
    Profile