A particle is projected in `x-y` plane with `y-`axis along vertical, the point of projection being origin. The equation of projectile is `y = sqrt(3) x - (gx^(2))/(2)`. The angle of projectile is ……………..and initial velocity is ………………… .

Options

A. `1ms^(-1)`
B. `2ms^(-1)`
C. `3ms^(-1)`
D. `1.2 ms^(-1)`

Answer

B

Explanation

Comparing with `y = x tan theta - (gx^(2))/(2u^(2)cos^(2)theta)` we have,
`tan theta = sqrt(3)` or `theta = 60^(@)` and `u^(2) cos^(2)theta = 1`
or `u = sec theta = sec 60^(@) = 2 ms^(-1)`