A particle moves along a parabolic path `y=-9x^(2)` in such a way that the `x` component of velocity remains constant and has a value `1/3m//s`. Find the instantaneous acceleration of the projectile (in `m//s^(2)`)

Options

A. `(1)/(3) ms^(-2)`
B. `3 ms^(-2)`
C. `(2)/(3) ms^(-2)`
D. `2ms^(-2)`

Answer

D

Explanation

Comparing with the trajectory of projectile in which particle is projected from certain height horizontally `(theta = 0^(@))`
`y = x tan theta - (gx^(2))/(2u^(2)cos theta)`
Putting `theta = 0^(@)` and `g = a = 18 u^(2) = 2 ms^(-2)`
`( :' y=- 9x^(2), u =(1)/(3) ms^(-1))`