A projectile has the maximum range of `500m`. If the projectile is now thrown up on an inclined plane of `30^(@)` with the same speed, what is the distance covered by it along the inclined plane?

Options

A. 250m
B. 500m
C. 750m
D. 1000m

Answer

B

Explanation

`(u^(2))/(g) = R_(max) = 500`
Now, `s = (u^(2))/(2a) = (u^(2))/(2g sin 30^(@)) = (u^(2))/(g) = 500 m`