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A projectile A is thrown at an angle 30^...

A projectile A is thrown at an angle `30^(@)` to the horizontal from point P. At the same time, another projectile B is thrown with velocity `v_(2)` upwards from the point Q vertically below the highest point A would reach. For B to collide with A the ratio `(v_(2))/(v_(1))` should be

A

`(sqrt(3))/(2)`

B

2

C

`(1)/(2)`

D

`(2)/(sqrt(3))`

Text Solution

Verified by Experts

The correct Answer is:
C

Vertical component of velocity of A should be equal to vertical velocity of B.
or `v_(1) sin 30^(@) = v_(2)` or `(v_(1))/(2) = v_(2)`
`:. (v_(2))/(v_(1)) = (1)/(2)`
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