A particle of mass 2kg moves with an initial velocity of `vec(v)=4hat(i) +4hat(j) ms^(-1)`. A constant force of `vec(F) =20hat(j)N` is applied on the particle. Initially, the particle was at (0,0). The x-coordinates of the particle when its y-coordinates again becomes zero is given by

Options

A. 3.2m
B. 6m
C. 4.8m
D. 1.2m

Answer

A

Explanation

Comparing with projectile motion we can see that it is like a projectile motion, with `u_(x) = 4 ms^(-1), u_(y) = 4 ms^(-1)` and `a_(y) = 10 ms^(-2)`
x-coordinate = Range `=(2u_(x)u_(y))/(g) = (2 xx 4 xx 4)/(10) = 3.2m`