A ball having charge `q` and mass `m` is suspended from a string of length `L` between two parallel plates where a vertical electric field `E` is established . Find the time period of simple pendulum if electric field is directed (a) downward and (b) upward.

A small ball having charge +q and mass m is suspended at one end of a light string of length and can rotate in vertical plane.A uniform electric field E exists in the region in vertically upward direction (mg>qE) .The minimum velocity required to be imparted to the ball at the lowest position in order to successfully negotiate the circular loop is sqrt(x(g-(qE)/(my))) then find x+y . x & y are lowest possible integer.

A simple pendulum having caharge q_1 mass ma and effective length 1 , is suspended from a rigid support between the plates of charged horizontal capacitor. Electric field in the capacitor is perpendicular to the plates and directed vertically downwards . The time period of oscillation of the pendulum. if plates are held vertically , is given by :

A simple pendulum having caharge q_1 mass ma and effective length 1 , is suspended from a rigid support between the plates of charged horizontal capacitor. Electric field in the capacitor is perpendicular to the plates and directed vertically downwards . The time period of socillattion of the pendulum is given by :

The electric field (vec( E)) between two parallel plates of a capacitor will be uniform if.

A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has mass m and charge q. The time period of the pendulum is given by:

A particle of mass 'm' and charge 'q' is suspended from the ceiling with the help of an insulating wire of length 'l' . It is placed in an uniform electric field as shown in figure. Then the time period of oscillation is