Home
Class 12
PHYSICS
A square surface of side L m is in the p...

A square surface of side `L m` is in the plane of the paper. A uniform electric field `vec(E )(V//m)`, also in the plane of the paper, is limited only to the lower half of the square surface (see figure). The electric flux in `SI` units associated with the surface is:

A

zero

B

`EL^(2)`

C

`EL^(2)//(2epsi_(0))`

D

`EL^(2)//2`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS

    DC PANDEY|Exercise Assertion and Reason|15 Videos
  • ELECTROSTATICS

    DC PANDEY|Exercise Match the columns|5 Videos
  • ELECTROSTATICS

    DC PANDEY|Exercise Check point 1.5|20 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITORS

    DC PANDEY|Exercise (C) Chapter exercises|50 Videos
  • GRAVITATION

    DC PANDEY|Exercise All Questions|120 Videos

Similar Questions

Explore conceptually related problems

A square surface of side L metre in the plane of the paper is placed in a uniform electric field E ("volt"//m) acting along the same place at an anlge theta with the horizontal side of the square as shown in figure. The electric flux linked to the surface in uint of V-m is

In a uniform electric field find the total flux associated with the given surfaces (R is radius )

In a uniform electric field find the total flux associated with the given surfaces (R is radius)

A uniform electric field vec E=ahat i+bhat j intersects a surface of area A .What is the flux through this area if the surface lies in the yz plane?

A square frame of edge 10 cm is placed with its ositivae normal making on angle of 60^0 with a uniform electric field of 20 V m^(-1) . Find the flux of the electric field through the surface bounded by the frame.

A cylinder of radius R and length l is placed in a uniform electric field E parallel to the axis of the cylinder. The total flux over the curved surface of the cylinder is

DC PANDEY-ELECTROSTATICS-Taking it together
  1. A charge 10 muC is placed at the centre of a hemisphere of radius R = ...

    Text Solution

    |

  2. Electric charge is uniformly distributed along a straight wire of radi...

    Text Solution

    |

  3. A square surface of side L m is in the plane of the paper. A uniform e...

    Text Solution

    |

  4. Which one of the following graphs represents the variation of electric...

    Text Solution

    |

  5. In a uniformly charged sphere of total charge Q and radius R, the elec...

    Text Solution

    |

  6. An electric dipole is situated in an electric field of uniform intensi...

    Text Solution

    |

  7. Two point charges (+Q) and (-2Q) are fixed on the X-axis at positions ...

    Text Solution

    |

  8. Charge q(2) of mass m revolves around a stationary charge q(1) in a ci...

    Text Solution

    |

  9. Four charges equal to -Q are placed at the four corners of a square an...

    Text Solution

    |

  10. The distance between the two charges 25 mu C and 36 muC is 11 cm. At w...

    Text Solution

    |

  11. The electric field at a point due to an electric dipole, on an axis in...

    Text Solution

    |

  12. If 10^(10) electrons are acquired by a body every second, the time req...

    Text Solution

    |

  13. ABC is an equilateral triangle. Charges -2q are placed at each corner....

    Text Solution

    |

  14. Two equally charged, indentical metal spheres A and B repel each other...

    Text Solution

    |

  15. Two point charges +10^(-7) C and -10^(-7)C are placed at A and B 20 cm...

    Text Solution

    |

  16. Infinite charges of magnitude q each are lying at x= 1,2,4,8….meter on...

    Text Solution

    |

  17. Two copper balls, each weighing 10 g are kept in air 10 cm apart. If o...

    Text Solution

    |

  18. A wooden block performs SHM on a frictionless surface with frequency, ...

    Text Solution

    |

  19. A thin conducting ring of radius R is given a charge +Q, Fig. The ele...

    Text Solution

    |

  20. Four point +ve charges of same magnitude(Q) are placed at four corners...

    Text Solution

    |