A proton moves at a speed `v = 2xx10^(6) m//s` in a region of constant magnetic field of magnitude B = 0.05 T. The direction of the proton when it enters this field is `theta = 30^(@)` to the field. When you look along the direction of the magnetic field, then the path is a circle projected on a plane perpendicular to the magnetic field. How far will the proton move along the direction of B when two projected circles have been completed?

Options

A. `4.35 m`
B. `0.209 m`
C. `2.82 m`
D. `2.41 m`

Answer

A