A photon of energy 5.4852eV liberates an...

A photon of energy 5.4852eV liberates an electron from the Li atom initially at rest. The emitted electron moves at right angles to the direction in which photon moves. Find the speed and the direction in which the `Li^(2+)` ion will move. lonization potential ofLi atom= 5.3918V.Atomic weight of `Li =6.94 g`,`N_(Av)=6.02xx10^(23)mol^(-1)andm_(e)=9.1xx10^(-31)kg`.

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