The resistivity of copper at room temperatrue is `1.7xx10^(-8) Omega m`. If the free electron density of copper is `8.4xx10^(28) m^(-3)`, find the relaxation time for the free electrons of copper. Given `m_(e)=9.11xx10^(-31) kg ` and `e=1.6xx10^(-19) C`.

If the density of copper is 8.9xx10^(3)kg//m^(3) , find its relative density.

If the free electron density of copper is 8.6xx10^(28)m^(-3) and resistivity of copper at room temperature is 1.7xx10^(-6)Omega cm , find the relaxation time for the free electrons of copper. Given, mass of electron =9.1xx10^(-31) kg , and charge of electron =1.6xx10^(-19)C .

If resistivity of copper conductor is 1.7xx10^(-8) Omega -m and electric field is 100Vm^(-1) , then current density will be

A current of 10 A is maintained in a conductor of cross-section 1 cm^(2) . If the free electron density in the conductor is 9 xx 10^(28) m^(-3) , then drift velocity of free electrons is

Calculate the relaxation time and mean free path at room temperature (i.e. 27^(@)C ). If the number of free electrons per unit volume is 8.5 xx 10^(28)//m^(3) and resistivity rho = 1.7 xx 10^(8) Omega-m . Given that mass of electron = 9.1 xx 10^(-31) kg e = 1.6 xx 10^(-19)C and k = 1 .36 xx 10^(-23) JK^(-1)

Calculate the speed of the electron in the first Bohr orbit given that h=6.6xx10^(-34) Js, m=9.11xx10^(-31) kg and e=1.603xx10^(-19) C .

Find the time of relation between collision and free path of electrons in copper at room temperature .Given resistance of copper = 1.5xx 10^(-8) Omega m number density of electron in copper = 8.5 xx 10^(28)m^(-3) charge on electron = 1.6 xx 10^(19)C , mass of electrons = 9.1 xx 10^(-19) kg Drift velocity of free electron = 1.6 xx 10^(-4)ms^(-1)

Electron density in a copper wire is 8.0 xx10^(22) cm ^(-3) . Calculate the relaxation time for electrons if the resistivity of copper is 1.68xx10^(-8) Omega m at room temperature. (Massof electron is 9.1 xx10^(-31) kg .)