A battery supplies a current of 0.9 A through a `2 Omega` resistor and a current of 0.3 A through a `7 Omega` resistor. Calculate the emf and internal resistance of the battery.

A battery of unknown emf and internal resistance is given to a student for the experiment. When student connects the battery to an external resistance of 10 Omega then 1A current flows through the circuit and when the same is connected to 15 Omega resistance then 0.75 A current flows through the circuit . Calculate the emf and internal resistance of the given battery.

By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is

Two identical cells connected in series send 1.0A current through a 5 Omega resistor. When they are connected in parallel, they send 0.8 A current through the same resistor. What is the internal resistance of the cell?

Current through 3Omega resistor is 0.8A, then potential drop through 4Omega resistor is

A 50 V battery is supplying current of 10 A when connected to a resistor. If the efficiency of the battery at this current is 25%, then the internal resistance of the battery is

A current of 2 A flows through a 2 Omega resistor when connected across a battery. The same battery supplies a current of 0.5 A when connected across a 9 Omega resistor. The internal resistance of the battery is

A current of 0.1 A flows through a 25 Omega resistor represented by the circuit diagram. The current in the 80 Omega resistor is

When a bettery is connected to the resistance of 10Omega the current in the circuit is 0.12 A the same battery gives 0.07A current with 20Omega calculate e.m.f and internal resistance of the battery.