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Period of revolution of the moon is 27.3...

Period of revolution of the moon is 27.32 days and its mean distance from earth is `384,400km`. Use the equation
`M_(1)+M_(2)=(4pi^(2))/G.(a^(3))/(T^(2))`
to calculate the sum of the masses of the earth and moon. Further, using the known fact that the earth moon system lies ate `4.75xx10^(6)m` from earth's centre, calculate the mass of each.

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Knowledge Check

  • If the distance of the moon from earth is and the period of revolution is T_(m) ,then the mass of the earth is

    A
    `(4pi^(2)r_(m)^(2))/(GT_(m))`
    B
    `(4pi^(2)r_(m)^(3))/(GT_(m)^(2))`
    C
    `(4pi^(2)r_(m))/(GT_(m))`
    D
    `(4pi^(2)r_(m))/(GT_(m)^(2))`

  • Masses of the earth and the moon are in the ratio 3:2 and the radii of the earth and the moon are in the ratio of 6:1 . The ratio of the weight of the body on their surface will be

    A
    `(1)/(12)`
    B
    `(1)/(24)`
    C
    `(12)/(1)`
    D
    `(24)/(1)`

  • The moon is 4xx10^(8)m from the earth. A radar signal transmitted from the earth will reach the moon in about

    A
    5.2 s
    B
    1.3 s
    C
    2.6 s
    D
    0.70 s

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