The total magnification produced by a compound microscope is `20`. The magnification produced by the eye piece is `5`. The microscope is focussed on a certain object. The distance between the objective and eye piece is observed to be `14 cm`. If least distance of distinct vision is `20 cm`, calculate the focal length of objective and eye piece.

(a) Draw a labelled ray diagram showing the formation of a final image by a compound microscope at least distance of distinct vision. (b) The total magnification produced by a compound microscope is 20. The magnification produced by the piece is 5. The microscope is focused on a certain object. The distance between the objective and eyepiece is observed to be 14cm. If least distance of distinct vision is 20cm, calculate the focal length of the objective and the eye piece.

The focal length of the eye-piece of compound microscope is

In a compound microscope magnification will be large, if the focal length of the eye piece is

The magnifying power of an astronomical telescope in the normal adjustment position is 100 . The distance between the objective and eye piece is 101 cm . Calculate the focal lengths of objective and eye piece.

For a total magnification of 175 from a compound microscope, the magnification produced by objective is 7 . What should be the magnification produced by eye piece ?

Magnification of a compound microscope is 30. Focal length of eye - piece is 5 cm and the image is formed at a distance of distinct vision of 25 cm . The magnificatio of the objective lens is

A compound microscope has a magnifying power 30 . The focal length of its eye-piece is 5cm . Assuming the final to be at the least distance of distinct vision (25 cm) , calculate the magnification produced by objective.

The magnification produced by the objective of a compound microscope is 8. If the magnifying power of the microscope be 32, then calculate the magnification produced by the eye piece.