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In L-R circuit l=l(0)[1-e^(-t//lamda)] ...

In `L-R` circuit `l=l_(0)[1-e^(-t//lamda)]`
Here `l=` electric current in the circuit. Then

A

the dimensions of `l_(0)` and `lamda`

B

the dimension of `t` and `lamda` are same

C

the dimensions o `l` and `l_(0)` are not same

D

All of the above

Text Solution

Verified by Experts

(b) Exponent has no dimensions
`:. [e^(-t//lamda)]=[M^(0)L^(0)T^(0)]` ltbr or `[-t/(lamda)]=[M^(0)L^(0)T^(0)]` or `[t]=[lamda] :. [lamda]=[T]`
Hence (b) is correct
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