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A block of 150kg is placed on an incline...

A block of `150kg` is placed on an inclined plane withh an angle of `60^(@)`. Calculate of the weight parallel to the inclined plane.

A

`1300N`

B

`1400N`

C

`1100N`

D

`750N`

Text Solution

Verified by Experts

(a) Component parallel to inclined plane, is `150 sin 60^(@)`.

`=(1500sqrt(3))/2=1299~~1300N`
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