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Two rings of radius R and nR made of sam...

Two rings of radius R and nR made of same material have the ratio of moment of inertia about an axis passing through center is `1:8`. The value of n is

A

2

B

`2sqrt(2)`

C

4

D

`1/2`

Text Solution

AI Generated Solution

To solve the problem, we need to find the value of \( n \) given that the ratio of the moments of inertia of two rings is \( 1:8 \). ### Step-by-step Solution: 1. **Understand the Moment of Inertia for a Ring**: The moment of inertia \( I \) of a ring about an axis passing through its center is given by the formula: \[ I = mR^2 ...
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Knowledge Check

  • Two rings of radii R and nR made from the same wire have the ratio of moments of inertia about an axis passing through their centres equal to 1:8. The value of n is

    A
    2
    B
    `2sqrt(2)`
    C
    4
    D
    `1/2`

  • Two circular loops A and B are made of the same wire and their radii are in the ratio 1:n . Their moments of inertia about the axis passing through the centre and perpendicular to their planes are in the ratio 1:m . The relation between m and n is

    A
    `m=n`
    B
    `m=n^(2)`
    C
    `m=n^(3)`
    D
    `m=n^(4)`

  • Two circular disc of same mass and thickness are made from metals having densities rho_(1) and rho_(2) respectively. The ratio of their moment of inertia about an axis passing through its centre is,

    A
    `rho_(1): rho_(2)`
    B
    `rho_(1)rho_(2):1`
    C
    `rho_(2):rho_(1)`
    D
    `1 : rho_(1)rho_(2)`

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