If a particle is moving on an parallel path given by `r=b cos omegat hati+asinomegat hatj`, then find its radial acceleration along `r`

Options

A. `omega r`
B. `omega^(2)r`
C. `-omega^(2)r`
D. none of these

Explanation

(a) `(dr)/(dt)=-bomegat sin hati+aomega cos omegat hatj`
`(d^(2)r)/(dt^(2))=-bomega^(2) sin omegat hati+aomega^(2) cos omegat hatj`
`(d^(2)r)/(dt^(2))=-omega^(2) [b cos omegat hati+a sin omegat hatj]=-omega^(2)r`