A particle is moving along a circular path with a constant speed `30m//s`. What is change in velociyt of a particle, when it describe and angle of `90^(@)` at the centre of the circle

Options

A. zero
B. `30sqrt(2)m//s`
C. `60sqrt(2)m//s`
D. `30sqrt(2)m//s`

Explanation

To find the change in velocity of a particle moving along a circular path when it describes an angle of 90 degrees at the center of the circle, we can follow these steps:

### Step 1: Understand the Initial and Final Velocities
When the particle moves along a circular path with a constant speed of 30 m/s, its velocity is always tangent to the circle at any point. Initially, let’s assume the particle is at point A on the circle, moving in the positive x-direction. Therefore, the initial velocity \( \vec{v_1} \) can be represented as:
\[ \vec{v_1} = 30 \hat{i} \text{ m/s} \]

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