Three blocks of masses `m_(1) = 1kg, m_(2)=2kg` and `m_(3) = 3kg` are placed in contact on a horizontal frictionaless plane as shown in figure. A force of 12 N is applied on `m_(1)`. Acceleration of the system is

Options

A. `12 m//s^(2)`
B. `2 m//s^(2)`
C. `6 m//s^(2)`
D. `4 m//s^(2)`

Answer

B

Explanation

The acceleration of the system is
`a=("Net force")/("Total mass")=(12)/(1+2+3)=(12)/(6)=2m//s^(2)`