A 0.1 kg body moves at a constant speed of 10 m/s. It is pushed by applying a constant force for 2 s. Due to this force, it starts moving exactly in the opposite direction with a speed of `4 m//s`. Then

Options

A. the deceleration of the body is `7 m//s^(2)`
B. the magnitude of change in momentum is 1.4 kg-m/s
C. impulse of the force is 1.4 N-s
D. All of the above

Answer

D

Explanation

`a=(v-u)/(t)=(-4-10)/(2)=-7m//s^(2)`
The magnitude of change in momentum
`=|m(v-u)|=14kg-m//s`=Impulse
Now, F = ma = 0.7 N