A car of 1400 kg kis moving on a circular path of radius 30 m with a speed of 40 km/h. When the drive applies the breaks and the carf conntinues to move along the circular path, what is the maximum deceleration possible if the types are limited to a horozontal friction of `10.6 kN`?

Options

A. `10 m//s^(2)`
B. `6.36 m//s^(2)`
C. `4 m//s^(2)`
D. None

Explanation

(b) the net acceleration to car is provided by force of friction.
`:. " " a=sqrt(a_(n)^(2)+a_(1)^(2))`
`:." "F=ma=msqrt(((v^(2))/(r))^(2)+a_(1)^(2))`
or `" " 10.6xx10^(3)=msqrt((v^(4))/(r^(2))+a_(t)^(2))`
After solving, " " `a_(t)=6..36 m//s^(2)`