A projectile is projected at a angle `60^(@)` with horozontal with speed 10 m/s. The minimum radius of curvature of the trajectory described by the projectile is

Options

A. `2.55 m`
B. 2 m
C. 10 m
D. None of these

Explanation

To find the minimum radius of curvature of the trajectory described by a projectile projected at an angle of \(60^\circ\) with a speed of \(10 \, \text{m/s}\), we can follow these steps:

### Step 1: Determine the initial velocity components
The initial velocity \(U\) can be broken down into horizontal and vertical components using trigonometric functions:
- Horizontal component:
\[ U_x = U \cos \alpha = 10 \cos 60^\circ = 10 \times \frac{1}{2} = 5 \, \text{m/s} \]
...