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The skate board negotiates the circular ...

The skate board negotiates the circular surface of radius `4.5 m` At `theta=45^(@)`, its speed of centre of mass is 6 m/s The comnined mas of skate board an dthe person is 70 kg and his centre of mass is `0.75 m` from the surface. The normal reaction between the surface and the skate board wheeol is

A

500 N

B

2040 N

C

1045 N

D

zero

Text Solution

Verified by Experts

(c) From the diagram,
`N-mg cos theta =(mv^(2))/(r)`
where , `r=CO=4.5-0.75=3.75 m`
`:." " N=(mv^(2))/(r)+mgcostheta`

From the figure , `theta=45^(@),=70 kg, g =9.8 n//s^(2)v'=6 m//s,r=4.5 m`
Putting these values in above equation, we get N=1050 N
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