A solid cylinder of mass 2kg rolls down (pure rolling) an inclined plane from a height of 4m. Its rotational kinetic energy, when its reaches the foot of the plane is (Take g=10m`s^(-2))`

Options

A. 20 J
B. 40 J
C. `80/3`J
D. 80 J

Explanation

To solve the problem, we need to determine the rotational kinetic energy of a solid cylinder that rolls down an inclined plane from a height of 4 meters. The mass of the cylinder is given as 2 kg, and we will use \( g = 10 \, \text{m/s}^2 \).

### Step-by-Step Solution:

1. **Calculate the Potential Energy (PE) at the Height**:
The potential energy of the cylinder at the height \( h \) is given by the formula:
\[
PE = mgh
...