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The moment of inertia of a circular disc...

The moment of inertia of a circular disc about an axis passing through the circumstances perpendicular to the plane of the disc is

A

`(MR^(2)`

B

`3/2MR[^(2)`

C

`(MR^(2))/2`

D

`5/4MR^(2)`

Text Solution

Verified by Experts

b) `I_(CM) = 1/2MR^(2)`
Now, moment of inertia about an axis is given as
`I = I_(CM) + Mh^(2) = 1/2MR^(2) + MR^(2)`
[as h= R]
`I = 3/2MR^(2)`
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