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1 kg mass of water, bolts at standard at...

1 kg mass of water, bolts at standard atmosphere pressure, turns completely into saturated vapour. Assume saturated vapour to be an ideal gas. Find the increment of internal energy of the system and internal work done. (Given, specific latent heat of avporisation of water=2250kJ/kg)

A

`3xx10^(6)J`

B

`2.1xx10^(6)J`

C

`3.2xx10^(6)J`

D

`4.2xx10^(6)J`

Text Solution

Verified by Experts

The correct Answer is:
b
We know, `DeltaG=DeltaU+DeltaW_(ax)+DeltaW_(in)`
`DeltaU=0,DeltaQ=mL`
`DeltaW_(ex)=P_(0)(V_("vapour")-V_("water"))=p_(0)V_("vapour")`
`PV=(m)/(M)RT`
`rArr DeltaW_(ax)=P_(0)V_("vapour")=(m)/(M)RT`
`DeltaW_(in)=DeltaQ-DeltaW_(ex)=mL-(m)/(M)RT`
`=m(L-(RT)/(M))=2.1xx10^(6)J`
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Knowledge Check

  • Change in internal energy when 4 kJ of work is done on the system and 1 kJ of heat is given out of the system is

    A
    `+ 1 kJ`
    B
    `- 5 kJ`
    C
    `+ 5 kJ`
    D
    `+ 3 kJ`

  • Change in internal energy, when 4 kJ of work is done on the system and 1 kJ of heat is given out by the system, is

    A
    `+1 kJ`
    B
    `-5 kJ`
    C
    `+5 kJ`
    D
    `+3 kJ`

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