Carbon dioxide contains `27.27%` of carbon, carbon disulphide contains `15.79%` of carbon and sulphur dioxide contains 50% of sulphur. This data is an agreement with

Options

A. Law of conservatino of mass
B. law of definite proportions
C. law of multiple proportions
D. law of reciprocal proportions

Explanation

d) In `CO_(2)`
Weight of `CO_(2)`= 100
Weight of carbon = 27.27
Weight of oxygen = 72.73
27.27 g of carbon combines with 72.73 g of oxygen 1 g of carbon combines with =`(72.73)/(27.27)` = 2.66` of oxygen
`therefore` Ratio of C and O in `CO_(2)` = 1:5.3`
If sulphur and oxygen were to combine to form `SO_(2)`, according to law of reciprocal proportions. They must combine in `5.3:2.66` or `2:1`.
In `SO_(2)`,the ratio of `S:O` is `1:1`.
thus, the ratio betweente two ratios is `2/1:1/1` = `2:1`
Since, the ratio of `S:O` is a simple whole numbers ratio, therefore law of reciprocal is proved.