The number of atoms in `4.25 g NH_(3)` is approximately:

Options

A. `1.505 xx 10^(23)`
B. `6.02 xx 10^(23)`
C. `3.01 xx 10^(23)`
D. None of these

Explanation

a) `therefore` 17 g of `NH_(3)` contains = `6.023 xx 10^(23)` molecules of `NH_(3)`
`therefore` 4.25 g of `NH_(3)` will contain = `(6.023 xx 10^(23)/(17) xx 425`
`=1.505 xx 10^(23)` molecules of `NH_(3)`