The total numebr of electrons present in 18 mL of water density=`1g`mL^(-1)` is

Options

A. `6.02 xx 10^(23)`
B. `6.02 xx 10^(23)`
C. `6.02 xx 10^(24)`
D. `6.02 xx 10^(25)`

Explanation

c) 18 mL `H_(2)O` = 18g of `H_(2)O` = 1mol
`=6.02 xx 10^(23)` molecules
`= 10 xx 6.02 xx 10^(23)` electrons
`6.02 xx 10^(24)` electrons