If `10^(21)` molecules are removed from 200g of `CO_(2)`, the number of mole(s) of `CO_(2)` left is/are

Options

A. `2.88 xx 10^(-3)`
B. `28.8 xx 10^(-3)`
C. `0.288 xx 10^(-3)`
D. `1.66 xx 10^(-2)`

Explanation

a) 200mg `CO_(2)` = 0.2 g = (0.2)/(44) mol = 0.00454 mol
`10^(21)` molecules of `CO_(2)` = (10^(21))(6.01 xx 10^(23))` = `1.66 xx 10^(-3)` mol
`therefore` Number of mole sleft = `(4.54 -1.66) xx10^(-3)=2.88 xx 10^(-3)`