The sulphate of a metal M contains `9.87%` of M. The sulphate is isomorphous with `ZnSO_(4).7H_(2)O`. The atomic weight of M is

Options

A. 40.3
B. 36.3
C. 24.3
D. 11.3

Explanation

c)As the given sulphate is isomophous with `ZnSO_(4).7H_(2)O`, its formula would be `MSO_(4).7H_(2)O`. It m is `MSO_(4).7H_(2)O` = m 32 + 64 1= 126 = m + 222
Hence, % of M = (m)/(m+222) xx 100 = 9.87 (given)
or 100 m = 987 m + 222 xx 9.87
or `90.13m = 222 xx 9.87` or m=24.3