A person adds 1.71 g of sugar `(C_(12)H_(22)O_(11))` in order to sweeten his tea. The number of carbon atoms added are (molecular mass of sugar = 342)

Options

A. `3.6 xx 10^(22)`
B. `7.2 xx 10^(21)`
C. 0.05
D. `6.6 xx 10^(22)`

Explanation

To find the number of carbon atoms added when 1.71 g of sugar (C₁₂H₂₂O₁₁) is dissolved in tea, we can follow these steps:

### Step-by-Step Solution:

1. **Calculate the number of moles of sugar (C₁₂H₂₂O₁₁)**:
\[ \text{Moles of sugar} = \frac{\text{mass of sugar}}{\text{molar mass of sugar}} = \frac{1.71 \, \text{g}}{342 \, \text{g/mol}} \]
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