The number of atoms in `4.25` g of `NH_(3)` is approximately

Options

A. `1 xx 10^(23)`
B. `1.5 xx 10^(23)`
C. `2 xx 10^(23)`
D. `6 xx 10^(23)`

Answer

D

Explanation

Mol.wt. of `NH_(3)=14+3=17`
`therefore` 17 g ammonia conatains atoms `=4xxN_(A)`
(`because` one molecule of `NH_(3)` has 4 atoms)
`therefore 4.25g` of ammonia contain atoms
`=(4xx6.02xx10^(23)xx4.25)/(17)=6.02xx10^(23)`atoms