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If we take 44 g of CO(2) and 14 g of N(2...

If we take 44 g of `CO_(2)` and 14 g of `N_(2)`. What will be the mole fraction of `CO_(2)` in the mixture?

A

`1/5`

B

`1/3`

C

`2/3`

D

`1/4`

Text Solution

Verified by Experts

Number of moles of `CO_(2)=(44)/(44)=1`
Number of moles of `N_(2)=(14)/28)=0.5`
`therefore` Mole of fraction of `CO_(2)=(1)/(1+0.5)=(1)/(1.5)or= (2)/(3)`
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