What volume of water is to be a added to `100cm^(3)` of 0.5 M NaOH solution to make it 0.1 M solution?

Options

A. 200 `cm^(3)`
B. 400 `cm^(3)`
C. 500 `cm^(3)`
D. 100 `cm^(3)`

Explanation

`M_(1)V_(1)= M_(2)V_(2)`
`0.5xx100=0.1xxV_(2)V_(2)=500cm^(3)`
Volume of water to be added to `100cm^(3)` of solution `=500-100 =400 cm^(3)`