How much water should be added to 200 mL of semi normal solution of NaOH to make it exactyly decinormal?

Options

A. 200 mL
B. 800 mL
C. 1000 mL
D. 11200 mL

Explanation

b) `N_(1)V_(1) = N_(2)V_(2)`, `1/2 xx 200 = 1/10 xx V_(2)`
`V_(2) = 1/2 xx 200 xx 10 = 1000mL`
`therefore` Volume of water added = 100-200 = 800 mL