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For the nuclear reaction, .(0)n^(1) to ....

For the nuclear reaction, `._(0)n^(1) to ._(1)H^(1) + ?`, the missing nuclide is

A

`._(-1)e^(0)`

B

`+._(1)e^(0)`

C

`._(1)H^(2)`

D

`._(2)He^(4)`

Text Solution

Verified by Experts

The correct Answer is:
a
`._(0)n^(1) to ._(1)H^(1) + ._(-1)e^(0)`
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