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The end product of the series, starting ...

The end product of the series, starting with `._(90)Th^(232)`, is

A

Pb-208

B

Pb-206

C

Bi-209

D

Pb-207

Text Solution

Verified by Experts

The correct Answer is:
a
`._(90)Th^(232)` is in `(232 = 4xx58 = 4n)` series. The end product of this series will be, thus Pb-208 as `(208 = 4xx52 =4n)`.
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