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The half-life of a radioactive isotope i...

The half-life of a radioactive isotope is 3 h. if the initial mass of the isotope was 300 g, the mass which remained undercayed in 18 h would be

A

1.17 g

B

9.36 g

C

2.34 g

D

4.68 g

Text Solution

Verified by Experts

The correct Answer is:
d
`N = N_(0)xx((1)/(2))^(n) = 300xx((1)/(2))^(6) = 4.68 g`
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