Home
Class 11
CHEMISTRY
An isotope of .(90)Th^(231) can be conve...

An isotope of `._(90)Th^(231)` can be converted into `._(90)Th^(227)` by the emission of

A

one `alpha`-particle

B

one `beta`-particle

C

two `alpha` and one `beta`-particle

D

one `alpha` and `2 beta`- particles

Text Solution

Verified by Experts

The correct Answer is:
d

Isotopes of an element can be obtained by emitting one `alpha`- and `2beta`- particles from its nucleus
`._(90)Th^(231) overset(-alpha)(to) ._(88)Ra^(227) overset(-beta)(to) ._(89)Ac^(227) overset(-beta)(to) ._(90)Th^(227)`
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    BITSAT GUIDE|Exercise BITSAT Archives|4 Videos
  • HYDROGEN

    BITSAT GUIDE|Exercise BITSAT Archives|5 Videos
  • P BLOCK ELEMENTS : GROUP 13,14

    BITSAT GUIDE|Exercise Archives|3 Videos

Similar Questions

Explore conceptually related problems

An isotope of ""^(231)Th can be converted into ""^(227)Th by the emission of

Thorium ._(90)Th^(232) is converted into ._(89)Pb^(208) by radioactive transformations. How many alpha -and beta -particles are emitted ?

e^(-) configuration of ._(90) Th-

In a process, ""_(92)U^(238) is converted to ""_(90)Th^(234) . Determine the particles emitted in the process and also write the equation for the given process.

Convert 90 km/h into m/s.

An isotope ._(92)U^(238) decays successively to form ._(90)Th^(234),._(91)Pa^(234),._(90)Th^(234),._(90)Th^(230) and ._(88)Ra^(226) . What are the radiations emitted in these five steps?

A radioactive decay chain starts from ._93 Np^237 and produces ._90 Th^229 by successive emissions. The emitted particles can be

The end product of the series, starting with ._(90)Th^(232) , is