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A sample of radioactive substance shows ...

A sample of radioactive substance shows an intensity of 2.3 millicurie at a time t and an intensity of 1.62 millicurie after 600 s. The half-life period of the radioactive metal is

A

1000 s

B

1187 s

C

1200 s

D

1500 s

Text Solution

Verified by Experts

The correct Answer is:
b
`(N_(0))/(N)=(2.30)/(1.62)`, Now, `lambda = (2.303)/(600)log(2.30)/(1.62) = 0.000584`
`:. T_(1//2) = (0.693)/(lambda) = (0.693)/(0.000584) = 1187s`
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