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The number of atoms in 100g of a fcc cry...

The number of atoms in 100g of a fcc crystal with density=`10gcm^(-3)` and cell edge as 200gm, is equal to

A

`3xx10^(25)`

B

`5xx10^(24)`

C

`1xx10^(25)`

D

`2xx10^(25)`

Text Solution

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(b) We know that, d `(Z.M)/(nxxa^(3))`
`n=(4xx100)/(10xx(200xx10^(-10))^(3))`
=`5xx10^(24)`
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