KCl crystallizes int the same type of lattic as done NaCl . Given that `r_(Na^(+))//r_(Cl^(-)) = 0.50` and `r_(Na^(+))//r_(K^(+)) = 0.70` , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl:

Options

A. 0.124
B. 1.1226
C. 0.891
D. 1.414

Explanation

(b) Given that `r_(Na^(+))//r_(Cl-)=0.74`
`r_(Na^(+))/r_(Cl-)=0.55`
`r_(Na^(+))/r_(Cl-)+1=0.55+1`
`(r_(Na^(+))r_(Cl-))/(r_(Cl^(-)))1.55.......(1)`
`(r_(K^+))/(r_(Cl^(-)))=0.74.......(2)`
`(r_(K^(+))r_(Cl-))/(r_(Cl^(-)))=1.74.......(2)`
Dividing Eq (ii) by Eq. (i)
`(r_(K^(+))+r_(Cl^(-)))/(r_(Na^(+))+r_(Cl^(-)))=(1.74)/(1.55)=1.1226.......(2)`